SkipLast
take all but the last item from an IEnumerable<T>
Source
public static IEnumerable<T> SkipLast<T>(this IEnumerable<T> source)
{
if (!source.Any())
{
yield break;
}
Queue<T> items = new Queue<T>();
items.Enqueue(source.First());
foreach(T item in source.Skip(1))
{
yield return items.Dequeue();
items.Enqueue(item);
}
}
Example
List<int> items = new List<int>(new[]{ 1, 2, 3, 4, 5, 6});
foreach(int item in items.SkipLast())
{
Console.WriteLine(item);
}
gets:
1
2
3
4
5
Author: Clinton Sheppard
Submitted on: 9 jun. 2009
Language: C#
Type: System.Collections.Generic.IEnumerable<T>
Views: 5037